a cricket ball of mass 100g moving with a speed of 3m/s is brought to rest by a player in 0.03 seconds .find the change in momentum
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Given:-
- Mass of ball ,m = 100g = 100/1000kg = 0.1 kg
- Initial velocity ,u = 3m/s
- Final velocity ,v = 0m/s
- Time taken ,t = 0.03 s
To Find :-
- Rate of Change Of Momentum , P
Solution:-
Using this Formula
Rate of change of Momentum
• P = mv-mu/t
where,
P is change of momentum
m is the mass
v is the final velocity
u is the initial velocity
Substitute the value we get
→ Rate of Change Of Momentum = 0.1×0 - 0.1×3/0.03
→ Rate of Change Of Momentum = 0 - 0.3/0.03
→ Rate of Change Of Momentum = -0.3/0.03
→ Rate of Change Of Momentum = -30/3
→ Rate of Change Of Momentum = -10kgm/s²
Therefore, the rate of change of momentum is -10kgm/s².
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