A cricket ball of mass 100g strikes the bat with speed 20ms–1
. The ball is played on in the same
direction with speed 30ms–1
. If the time of contact of ball with the bat is 0.1s calculate the change
in momentum of the ball and the average force applied by the ba
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weight of cricket ball, m = 100g = 0.1 kg
speed of cricket ball, v = 20 m/s
so, initial linear momentum of ball, = mv = 0.1 × 20 = 2 kgm/s
a/c to question, after striking a bat , ball remains in contact with it for 0.1 sec.
so, final linear momentum , = 0
now, change in linear momentum = 2 - 0 = 2kgm/s
we know, force = change in momentum/time
= 2/0.1 = 20 N
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