A cricket ball of mass 120g is moving with a velocity of 12m/s and is hit by a bat so that the ball is turned back with a velocity of 20m/s. If duration of contact between ball and bat is 0.001s.Find the impulse and the average force exerted on the ball by the bat
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1
Answer:
Impulse=F×t= Change in Momentum
⇒ Change in Momentum =mv−mu=0.15(12)−0.15(−20)=4.8
⇒F×0.001=4.8
⇒F=4800N
Therefore, A is correct option.
Explanation:
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