Question

A cricket ball of mass 125 g collides with a bat with
speed 20 m/s and return with same speed along
same line within 0.01 seconds. The force acted on
bat is
(2) 50 N
(1) 25 N
(3) 250 N
(4) 500 N​

Answer 1

=> ANSWER ==> (4)= 500 N

Given:-

• The mass of cricket ball = 125g

• Final velocity of ball (v) = + 20 m/s

• Initial velocity of ball (u) = - 20 m/s

• Time taken by ball on returning = 0.01s

To Find:-

• The force acted on bat = ?

Solution:-

To calculate force acted on bat at, first we have to find mass and acceleration by applying formula of motion. we know that Force = mass × acceleration:-

As per the 1st equation of motion :-

==> v = u + a t

==> 20 = - 20 + a × 0.01

==> 40 = 0.01a

==> a= 40/0.01

==> a= 4000 m/s²

Now change the mass of cricket ball in kg:-

==> 1kg = 1000 g or 10³

==> mass of cricket ball = 125 / 1000 kg

==> mass of cricket ball = 0.125 kg

Now calculate force acted on bat:-

==> Force = mass × acceleration

==> Force = 0.125 × 4000

==> Force = 500 N

Hence,

• Force acted on bat = 500 N

Answer 2

Given :-

A  cricket ball of mass 125 g collides with a bat with  speed 20 m/s and return with same speed along  same line within 0.01 seconds.

To Find :-

Force acted

Solution :-

At first we need to find acceleration

$\dag \bf Acceleration$

Acceleration is the change in velocity by an object with respect to time.

$\bf a = \dfrac{v-u}{t}$

a = Acceleration

v = Final Velocity

u = Initial Velocity

t = Time

$\sf a = \dfrac{20 - (-20)}{0.01}$

$\sf a = \dfrac{20 + 20}{0.01}$

$\sf a = \dfrac{40}{0.01}$

$\sf a=4000 \; m/s^2$

We know that

1 kg = 1000 g

Mass of bat is 125 g

125 g = 125/100 = 0.125 kg

Now

Force is the product of mass and acceleration

$\dag \bf F = ma$

$\sf F = (0.125)(4000)$

$\sf F = 500 \; N$