A cricket ball of mass 145 g is moving with a velocity of 14 m/s and is being hit by a bat ,so that the ball is turned back with a velocity 22m/s .the force of below acts on the ball for o.o15s .find out the average force exerted by bat on ball
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Answered by
2
acceleration =(22-(-14))/0.015 becoz direction had changed
@=36/0.015=2400m/second square
f=m×a=0.145×2400
@=36/0.015=2400m/second square
f=m×a=0.145×2400
Answered by
3
Answer:
Explanation:
To find :
F = ?
Solution :
As,
➸ F x t = Impulse = change in momentum
➸ F x 0.01
➸ m (v - u)
➸ 0.150 (- 20 - 12)
➸ F = -0.15 x 32/0.01
....
➸ F = - 480N
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