Question

A cricket ball of mass 15 kg moving with a speed of 5 m/s is brought to rest by a cricketer in 10 sec.Calculate the force applied by the cricketer​

Answer 1

HEY MATE,LET ME HELP YOU WITH YOUR QUERY!:D

Mass of the ball, m =15 kg.

Initial velocity of the ball, u = 5 m/s.

Finally, it comes to rest, v = 0.

Time, t = 10 s

NOW,WE KNOW,FORCE=MASS X ACCELERATION

HERE,FORCE=15 KG X ACCELERATION

ALSO,ACCELERATION=(FINAL VELOCITY-INITIAL VELOCITY)/TIME

=>0-5/10=-5/10=-1/2 M/S^2

HENCE,FORCE= 15 KG X -0.5 M/S^2

=>FORCE= -7.5 KG-M/S^2 OR -7.5 NEWTON.

SO HOPE YOU ARE HELPED MATE,PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST...

Answer 2

Answer:

-7.5 N

Explanation:

m = 15 kg

u = 5 m/s

v = 0 m/s

t = 10 s

Final Momentum (mv) = 15x0 = 0 kgm/s

Initial Momentum (mu) = 15x5 = 75 kgm/s

Change in Momentum = mv - mu

= 0 - 75

= -75 kgm/s

$force \: = \frac{change \: in \: momentum}{time}$

$force = \frac{ - 75}{10} = - 7.5 \: N$

Negative sign indicates that the force applied was against the direction of motion.