A cricket ball of mass 150 g moving at a speed of 20 m/s is brought to rest by a player in 0.03 s . Find the average force applied by the player. Ans-0.125 N
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Explanation:
mass of the ball (m) =150g or 0.15kg
initial velocity (u) =20 m/s
time (t) = 0.03sec.
final velocity (v) = 0
Initial momentum = mu
= 0.15×20
= 3 kgm/s
Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu
= 0 - 3 = -3 kgm/s
Average force = Changeinmomentum /time
= -3/0.03
= -100N
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