A cricket ball of mass 150 g moving at a speed of 25 m/s is brought to a rest by a player in 0.03 sec.Find the average force applied by the player
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Answered by
5
Answer:
Using Impulse-Momentum Principle,
I=Δp (I - Impulse, p - momentum)
F x Δt=Δp
F x 0.03=0.15 x 25
F x 0.03=3.75
F=3.75/0.03
F=125N
Answered by
3
Answer:
Mass, m = 150g = 0.15kg
Speed, v = 25m/s
Time, t = 0.03sec
So
=> F = ma
To find a (acceleration) we use
=> a = v/t
=> a = 25/0.03
=> a = 833.34
Now to find Force we use
=> F = ma
=> F = 0.15kg × 833.34
=> F = 125N
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