Question

A cricket ball of mass 150 g moving at a speed of
25 ms-1 is brought to rest by a player in
0.03 s. Find the average force applied by the
player.
•Please give step by step explanation..

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Answer 1

Answer:

A cocker ball of mass 150 g moving

Answer 2

Answer:

Given:-

m=150 g (0.15kg)

$u = 25m {s}^{ - 1}$

$v = 0m {s}^{ - 1}$

t=0.03 s

$a = \frac{v - u}{t}$

$a = \frac{(0 - 25)}{0.03}$

$a = \frac{ - 25}{0.03}$

$a = \frac{ - 2500m {s}^{ - 2} }{3}$

Now,

Force=mass×acceleration

$= \frac{ - 2500}{3} \times 0.15$

$= - 2500 \times 0.05$

= -125 N

Average force applied is 125 N, opposite to the direction of force.