A cricket ball of mass 150 g moving at a speed of
25 ms-is brought to rest by a player in
0.03 s. Find the average force applied by the
player.
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Given :-
A cricket ball of mass 150g moving at a speed of 25 ms^-1 is bought to rest by a player in 0.03s
To Find :-
Average force
Solution :-
We know that
v = u + at
0 = 25 + a(0.03)
0 - 25 = 0.03a
-25 = 0.03a
-25/0.03 = a
-2500/3 = a
Now
1 kg = 1000 g
150 g = 150/1000 = 0.15 kg
F = ma
F = 0.15 × -2500/3
F = 15/100 × (-2500)/3
F = -125 N
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