a cricket ball of mass 150 grams has an initial velocity 3i+ 4j m/s and final velocity is equal to - 3i+ 4j m/s , after being hit .The change in momentum will be
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cricket ball of mass 150 g has an initial velocity u = (3Î + 4ĵ ) ms-1 and a final velocity v = - (3Î + 4ĵ) ms-1 after being hit. The change in momentum (final momentum - initial momentum) is (in kg. ms-1).
(a) zero
(b) -(0.45Î + 0.6ĵ)
(c) -(0.9ĵ + 1.2ĵ )
(d) -5(Î + ĵ)
takes place always in the direction of the force applied.
We know that F = df/ dt
According to the question that the meter scale is moving with uniform velocity, hence, change in momentum will be zero, i.e. dp = 0
This implies momentum will remains same. So, Force = F= 0.
So, we can say that all parts of the meter scale is moving with uniform velocity because total force is zero and if there is any torque acting on the body this means that the body will be in rotational motion which means that the direction of velocity will be changing continuously. So, the torque acting about centre of mass of the scale is also zero.
(a) zero
(b) -(0.45Î + 0.6ĵ)
(c) -(0.9ĵ + 1.2ĵ )
(d) -5(Î + ĵ)
takes place always in the direction of the force applied.
We know that F = df/ dt
According to the question that the meter scale is moving with uniform velocity, hence, change in momentum will be zero, i.e. dp = 0
This implies momentum will remains same. So, Force = F= 0.
So, we can say that all parts of the meter scale is moving with uniform velocity because total force is zero and if there is any torque acting on the body this means that the body will be in rotational motion which means that the direction of velocity will be changing continuously. So, the torque acting about centre of mass of the scale is also zero.
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