a cricket ball of mass 150 grams moving at a speed of 25 metre per second is brought to rest by a player in zero. 0 3 seconds. find the average force applied by the player
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Answer :
Step by step explanation :
Mass of ball = 150g = 0.15 kg
Initial velocity = 30 m/s
Time = 0.3 secs
Final velocity = 0
Initial momentum = mu
0.15 × 30 = 4.5 kg m/s
Final momentum = mv = 0
Change in momentum = mv-mu
0-4.5 = -4. 5 kg m/s
Average Force = change in momentum/ time
-4. 5/0.3
= -15 N
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