A cricket ball of mass 150g is moving with a velocity of 12m/s and is hit by a bat, so that the ball is turned back with a velocity of 20m/s. The force of the blow acts for 0.01s on the ball. Find the average force exerted by the bat on the ball.
Answers
Answered by
455
We know that Force = Impulse/ Time
Impulse = mass * change in velocity
Time = 0.01 s
Mass m = 150 g = 1.5 x 10 ̄ ¹ kg
Change in velocity = Final - intial velocity = 20 - (-12) = 32 m/s
Therefore Force = mass * change in velocity / time = 1.5 x 10 ̄ ¹ x 32 / 0.01
= 15 x 32 = 480 N
Average force on the ball is 480 N
Answered by
172
Here, we have
Mass of the ball, m = 150 g = 0.15 kg
Initial speed of the ball, u = -12 m/s
Final speed of the bal after being hit, v = 20 m/s
Impulse = change in momentum = final momentum initial momentum
= Impulse = 0.15 × 20 0.15 × (-12) = 4.8 Ns
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