Social Sciences, asked by kanhaiyaklsiet9010, 1 year ago

A cricket ball of mass 150g is moving with a velocity of 12m/s and is hit by a bat, so that the ball is turned back with a velocity of 20m/s. The force of the blow acts for 0.01s on the ball. Find the average force exerted by the bat on the ball.

Answers

Answered by Answers4u
455

We know that Force = Impulse/ Time

Impulse = mass * change in velocity

Time = 0.01 s

Mass m = 150 g = 1.5 x 10 ̄ ¹ kg

Change in velocity = Final - intial velocity = 20 - (-12) = 32 m/s

Therefore Force = mass * change in velocity / time = 1.5 x 10 ̄ ¹ x 32 / 0.01

= 15 x 32 = 480 N

Average force on the ball is 480 N

Answered by Arslankincsem
172

Here, we have


Mass of the ball, m = 150 g = 0.15 kg


Initial speed of the ball, u = -12 m/s


Final speed of the bal after being hit, v = 20 m/s


Impulse = change in momentum = final momentum initial momentum


= Impulse = 0.15 × 20 0.15 × (-12) = 4.8 Ns


Similar questions