Question

A cricket ball of mass 150g is moving with a velocity of 12m/s and is hit by a bat,so that the ball is turned back with a velocity of 20m/s .The force of the blow acts for 0.01 second on the ball.Find the average force exerted by the bat on the ball.

Answer 1

Average force exerted= Change in momentum /time

F=Δp/t

F=m(v-u)/t

F =0.15(20-(-12))/0.01

F=0.15×32/1/100

F= 0.15×32×100

F= 480 N

Answer 2

Answer:

Explanation:

A 150 g cricket ball moving at a speed of 12 m s-1 is

hit by a bat and turned back at a speed of 20 m s-1.

The duration of impact is 0.01 s. What is the average

force exerted on the ball by the bat?

Given :

m = 150

g = 0.15 kg,

u = 12 m/s^-1

v= -20 m/s^-1

t = 0.01 s,

To find :

F = ?

Solution :

As,

➸ F x t = Impulse = change in momentum

➸ F x 0.01

➸ m (v - u)

➸ 0.150 (- 20 - 12)

➸ F = -0.15 x 32/0.01

➸ F = - 480N