Question

A cricket ball of mass 150g moves at a speed of 12m/s and after hitting by the bat it is deflected back at the speed of 20m/s

Answer 1

Answer :

Mass of cricket ball = 150g

• 150g = 0.15kg

Initial velocity of ball = 12m/s

Final velocity of ball = 20m/s

Time = 0.02s

We have to find impulse and average force exerted on the ball by the bat$.$

★ Impulse (J) is measured as the change of linear momentum.

➝ Impulse = ∆ (Momentum)

➝ J = m ∆v

➝ J = m (v₂ - v₁)

• v₂ denotes final velocity
• v₁ denotes initial velocity

➝ J = 0.15 × [20 - (-12)]

Negative sign shows opposite direction!

➝ J = 0.15 × 32

➝ J = 4.8 N s

★ As per newton's second law of motion, Force is defined as the rate of change of linear momentum.

Mathematically, F = dp/dt

By substituting the values, we get

➠ F = dp/dt

➠ F = 4.8/0.02

➠ F = 240 N

∴ (3) is the correct answer!