Question

a cricket ball of mass 150g moving at a speed 25 m/s is brought to rest by a player in 0.03s. find the average force applied by the player PLS ANSWER FAST

Answer 1

Answer:

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Answer 2

Given :-

• Mass of cricket ball , m = 150 g = 0.15 kg  
• initial velocity of ball, u = 25 ms⁻¹
• final velocity of ball, v = 0 (rest)
• time taken for velocity change, t = 0.03 s

To find :-

• Average force applied by player to bring the ball to rest.

Formula used :-

• Formula to calculate acceleration

$\boxed{\red{\bigstar}\sf{acceleration=\dfrac{final \:velocity-initial\:velocity}{time\:taken}}}$

• Formula to calculate Force

$\boxed{\red{\bigstar}\sf{Force =mass\times acceleration}}$

Solution :-

Calculating acceleration of ball while coming to rest

$\longmapsto\sf{acceleration,a=\dfrac{v-u}{t}}\\\\\\\longmapsto\sf{a=\dfrac{0-25}{0.03}}\\\\\\\longmapsto \overbrace{\underbrace{\sf{a=\dfrac{-2500}{3}\;\;ms^{-2}}}}$

Calculating Force applied by Player on the ball to stop it

$\longmapsto\sf{Force,F=m\times a}\\\\\\\longmapsto\sf{F=0.15\times \dfrac{-2500}{3}}\\\\\\\longmapsto\red{\overbrace{\underbrace{\underline{\underline{\large{\sf{F=-125\:N}}}}}}}$

Hence,

125 Newton of force is applied by Player to bring the ball to rest . and the negative sign with the magnitude shows that Force is applied in the direction opposite to motion of ball.