Question

A cricket ball of mass 150g moving with velocity 15m/s is brought to rest by a player in 0.05 s .Calculate the intial the impulse and Average force exerted by a player.

Answer 1

Answer:

Mass of ball, m=150g=0.15Kg

Velocity, v=20m/s

Time, t=0.1sec

Momentum, p=mv

Force,

F= time upon

momentum

F= t upon

mv

F= 0.1 upon

0.15×20

F=30N

So, the force exerted be the ball is 30N.

Impulse,

J=force×time

J=30×0.1

J=3Ns

Answer 2

Given

• Mass = 150 g
• Initial Velocity = 15 m/s
• Final Velocity = 0 m/s
• Time = 0.05 s

To Find

• Impulse
• Average Force

Solution

☯ Impulse = Change in Momentum

• And the change of momentum is given by, mv - mu or m(v-u)

☯ Average Force = Impulse × Time

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✭ According to the Question :

➞ Impulse = Change in Momentum

➞ Impulse = m(v-u)

• Mass = 150 g = 150/1000 = 0.15 kg
• Initial Velocity = 15 m/s
• Final Velocity = 0 m/s

➞ Impulse = 0.15(0-15)

➞ Impulse = 0.15 × (-15)

➞ Impulse = -2.25 Kg m/s

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Average Force :

➞ Avg Force = Impulse × Time

➞ Avg Force = (-2.25) × 0.05

➞ Avg Force = -0.1125 N

• The negative sign shows us that both the vectors are in opposite direction of the motion to the ball