Question

A cricket ball of mass 150grams is moving with a velocity 15m/s is brought to the rest by the player in 0.05 sec.Calculate the force exerted by the player??​

Answer 1

Answer:

m = 150 gm or 0.015 kg

m = 150 gm or 0.015 kgu = 15m/s

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/s

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 sec

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/t

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/ta = (0 - 15)/0.1

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/ta = (0 - 15)/0.1= -150

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/ta = (0 - 15)/0.1= -150F = ma

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/ta = (0 - 15)/0.1= -150F = ma= (0.015)(150)

m = 150 gm or 0.015 kgu = 15m/sv= 0 m/st = 0.1 secWe know that , a = (v-u)/ta = (0 - 15)/0.1= -150F = ma= (0.015)(150)= 2.25 N