Question

A cricket ball of mass 200 gm moving with a speed of 40 m/s is broukht to test by
player in 0.04.
Calculate the following:
change in momentum of the ball,
average force applied by the player.​

Answer 1

Answer:

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Answer 2

Answer:

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PHYSICS

A cricket ball of mass 100 g is moving with speed of 25 m/s and is brought to rest in 0.025 s. find the average force applied.

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ANSWER

mass of the ball (m) =100g or 0.1kg

initial velocity (u) =25

s

m

time (t) = 0.025sec.

final velocity (v) = 0

Initial momentum = mu

= 0.1×25

= 2.5

s

kgm

Final momentum = mv (which is equal to 0, since v is zero)

Change in momentum = mv-mu

= 0 - 2.5 = -2.5

s

kgm

Average force =

time

Changeinmomentum

= -

0.025

(2.5)

= -100

s

kgm

= -100 N

The negative sign actually shows that the force was applied

opposite to the direction of the motion of the ball.

So, the average force applied by the player will be 100