Question

a Cricket ball of mass 200g is moving with velocity of 40m/s is brought to rest by a player in 0.6sec. What is the impulse on the ball and find the average applied force by the player

Answer 1

Answer:

The impulse on the ball is $=8N$

Average force is$=13.3 N$

Explanation: Given:

Mass $=200g$

Velocity $=40m/s$

Rest by a player is $0.6sec$

Find, the impulse on the ball and find the average applied force by the players.

Solution: Impulse $=$ change in momentum

$= m (v-u)$

$=$ $0.2(0-40)=-8Ns$

Average force $=$ $\frac{Impulse}{Time}=\frac{-8}{0.6}sec$

$=13.3N$

Hence, the impulse on the ball is $-8N$

Average force is $-13.3N$

#SPJ2