A cricket ball of mass 200g moving with a speed of 48 ms i beaught l5 rest by a player in 0.05 s. Find (i the change in momentum of the ball (ii) the average force applid by the
player
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To find.
1) = The change in momentum of the ball.
2) = The average force applied by the
player.
EXPLANATION.
Mass of cricket ball (m) = 200g = 0.2 kg
initial velocity = 48 m/s
Time (t) = 0.05 seconds
Final velocity ( v) = 0
initial momentum = mu
=> 0.2 X 48 = 9.6 kgm/s
Final momentum = mv
=> 0.2 X 0 = 0
change in momentum = mv - mu
=> 0 - 9.6 = -9.6 kgm / s
Average force =
=> change in momentum / time
=> - 9.6 / 0.05
=> -192 kgm / s
=> -192 N
Negative sign actually shows that the force
was applied opposite to the direction of the
motion of the ball.
Therefore,
1) = change in momentum = -9.6 kgm/s
2) = average force applied = -192 N
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