Question

A cricket ball of mass 300g travelling at 15m/s is struck by a cricket bat so as to return it
along its original path with a velocity of 10m/s. Calculate the change of momentum occurred in the motion of the cricket ball by the force applied by the cricket bat .
(a) - 10kgm/s (c) -15kgm/s
(b) -5kgm/s (d) – 7.5kgm/s
(2 Points)​

Answer 1

Explanation:

Mass of ball(m)=200g=0.2kg

Initial velocity of ball(u)=10ms−1

Final velocity of ball(v)=5ms−1

Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms−1=−3 Ns

apply the same method