Question

A cricket ball of mass 50 g is moving with a speed of 20 m/s is brought to rest by a player in 0.5 s. Find the average force

Answer 1

Explanation:

given mass = 50g = 0.05kg

initial velocity = 20 m/s

final velocity = 0

time =0.5 s

$a \: = \: \frac{v - u}{t} \\ a \: = \: - \frac{20}{0.5} \\ a \: = \: - 40m {s}^{ - 2} \\ force = ma \\ f = 0.05 \times 40 \\ f = 2 \: newtons$