Question

a cricket ball of mass 50 gram moving with a velocity of 0.75 metre per second is stopped by a player in 0.75 second what is the force applied by the player to stop the ball​

Answer 1

Step-by-step explanation:

mass of the body = 50 gram

velocity = 0.75 /s

initial velocity = 0.75

final velocity = 0

acceleration = final velocity - initial velocity /time

= 0-0.75/0.75

= -1m/s

force = m×a

force = 50×-1

= -50 Newton