Question

A cricket ball of mass 50g moving with the velocity of 1m/s is stopped by the player in 0.5sec.What is the force applied by the player to stop the ball

Answer 1

M= 50/1000

= 1/20 kg

A= v-u/t

=1-0/0.5

= 2m/s^2

F=ma

= 1/20× 2

= 1/10Kgm/s^2