Question

A cricket ball of mass 70 g moving with a velocity of 0.5 m/s is stopped by a player in 0.5 sec. What is the force applied by the player to stop the ball?

Answer 1

Answer:

Final velocity is 0 because the ball is stopped. We now calculate the force applied to stop the ball. This can be calculated using the formula: In this case, the negative sign shows that the force is a retarding force.

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Answer 2

Given:-

Mass of the cricket ball(m)=70g

=>70/1000

=>0.07kg

Initial velocity(u)=0.5m/s

Final velocity(v)=0 (as it finally comes to rest)

To find:-

Force exerted by the player(F)

Solution:-

We know that----

=>a=v-u/t

=>a=0-0.5/0.5

=>a= -0.5/0.5

=>a= -1m/s²

Now,by Newton's second law of motion,we know that---

=>F=ma

=>F=0.07×(-1)

=>F= -0.07N

Thus,the force applied by the player is -0.07N or a retarding force of 0.07N.