Physics, asked by XxKILLSHOTxX, 3 months ago

A cricket ball of mass 70 g moving with a velocity of 0.5 m/s is stopped by a player in 0.5 s. What is the force applied by the player to stop the ball?​

Answers

Answered by Anonymous
3

Answer:

mass of ball=70g=0.07 kg

velocity of ball=0.5 m/s

impulse=rate of change of momentum=m(v-u)=0.07(0-0.5)=0.07×-0.5=-0.035 Ns

impulse =force ×time

-0.035=force ×0.5

-0.035÷0.5=force applied

-0.07 N=force applied

Answered by sayalidoshi315
1

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