Question

A cricket ball of mass 70 g moving with a velocity of 3m/s is stopped by a player in 0.5 s. What is the magnitude of 
force applied by the player to stop the ball? ​

Answer 1

Answer:

Here, m= 70 g = 0.070 kg

         u=  3m/s

         v= 0

          t= 0.5 s

         

Explanation:

Force, F = m (v-u/t) = 0.070 (0 - 3/0.5) = -6 N.

Negative sign shows the retarding nature of the force.