Question

a cricket ball of mass 70 gram is moving with a velocity of 0.5 metre per second is stopped by a player in 0.5 S. what is the force applied by the player to stop the ball​

Answer 1

Answer:

-0.07N

Explanation:

mass of ball=m= 70g= 0.07kg

initial velocity=u= 0.5m/s

final velocity=v= 0m/s

time=t=0.5 sec

a=v-u/t

0-0.5/0.5

= -1m/s²

F= m×a

0.07 - 1

-0.07N

ans.

HOPE ITS HELPFUL...