Question

A cricket ball of mass 70 gram moving with a speed of 0.5 metre per second is stopped by a player in 0.5 seconds what is the force applied by player to stop the ball

Answer 1

Ft=mv
F=mv/t
F=.070x0.5/0.5=0.07N
it may help.

Answer 2

F = mv/t

F = 70 * 10^-3 * 0.5 / 0.5

F = 70 * 10^-3 N