Question

a cricket ball of mass 70 kg moving with a velocity of 0.5 metre per second is stopped by a player in 0.5 seconds find the force applied by the player​

Answer 1

Given:

mass of ball =m=70g=0.070kg

Initial velocity=u= 0.5 m/s

Final velocity =v=0m/s

time=t= 0.5 sec

a= v-u/t

⇒0-0.5/0.5

⇒-1 m/s²

F=m*a

⇒0.07x-1

⇒-0.07 N

Answer 2

Answer:

This is the answer⬆

Explanation:

check it