Question

A CRICKET BALL OF MASS 70g IS MOVING IN A VELOCITY OF O.5ms IS STOPPED BY A PLAYER IN 0.5ms WHAT IS THE FORCE APPLIED BY A PLAYER TO STOP THE BALL.

Answer 1

m=70g=0.07kg
u=0.5m/s
t=0.5sec
v=0m/s
A=v-u/t

$(0 - 0.5) \div 2$
=(-0.25m/s square)

F=m*a
=0.07*(-0.25)
=(-0.0175 N)
negative sign shows opposite direction of force and Motion

Answer 2

HERE IS YOUR ANSWER

HOPE IT WILL HELP YOU