Question

A Cricket ball of mass 70g moving with a.velocity of 0.5 m/s is stopped by a player in0.5 s . what is the force applied by the player to stop the ball​

Answer 1

Answer:

Explanation:

Given:

mass of ball =m=70g=0.070kg

Initial velocity=u= 0.5 m/s

Final velocity =v=0m/s

time=t= 0.5 sec

a= v-u/t

⇒0-0.5/0.5

⇒-1 m/s²

F=m*a

⇒0.07x-1

⇒-0.07 N

Answer 2

Answer:

Given,

mass,m=70g

velocity,u=0.5m/s

final velocity,v=0m/s

time taken,t=0.5sec

Force acting on the ball, F= m(v-u/t)

                                             =0.070(0-0.5/0.5)

                                              = -0.07N

Negative sign shows the retarding nature of the force.