Question

A cricket ball of mass 70g moving with a velocity of 0.5m/s is stopped by a player in 0.5s . what is the force applied by the player to stop the ball

Answer 1

We shall first calculate the deceleration

a = (v - u) / t

here,

v = 0

u = 0.5 m/s

t = 0.5s

so,

a = (0 - 0.5) / 0.5

thus,

a = -1 m/s2

now, the force applied will be given as

F = ma

here.

m = 70 g = 0.070 kg

so,

F = -1 x 0.070

thus,

F = -0.07 N

Answer 2

gravitational force and pressure applyied on it