Physics, asked by nimil5333, 8 months ago

a cricket ball of mass 70g moving with a velocity of 0.5m/s is topped by a player in 0.5 s. what is the force applied by the player to stop the ball

Answers

Answered by UTharun

Answer:

I think 35 decimeters . But I dont know correctly. I think the answer is Speed =70g/0.5m is equal to 35 decimeters.(10 decimeters is equal to 1 meter .)

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