Question

A cricket ball of mass 70g moving with a velocity of 0.5per Sec is stopped by a player in 0.5sec. what is the Force applied by the player to stop the ball

Answer 1

we know that F=ma
i.e. f= ?
m is 70g
a is o.5 sec
f=70×o.5=35pasacal

Answer 2

mass=70 gm

initial velocity (u) =0.5 m/s

time=0.5 sec

final velocity (v) =0 m/s as the ball is stopped by the player.

acceleration = (v-u)/t = (0-0.5)/0.5=-0.5/0.5=-1 m/Sec2.

we know force =mass*acceleration=70 * -1 =70 N (answer)