Question

• A Cricket ball of mass 70gram moving with a velocity of 0.5m/s is stopped by a player in 0.5 s. what is the for e applied by the player to stop the ball​

Answer 1

Answer:

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Explanation:

m=70g

u=0.5m/s

v=0

t=0.5s

F=ma

=m(v-u)/t

=70(0-0.5)/0.5

=70×-0.5/0.5

= -35/0.5

= -70N