Question

A cricket ball of mass70g

moving with a velocity of

0.5 m/s is stopped by a

player in 0.5 s. What is

the force applied by the

player to stop the ball?

Answer 1

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⭐⭐⭐⭐ SOLUTION ⭐⭐⭐⭐

MASS OF CRICKET BALL (m) = 70 g = 0.07 kg.
INITIAL VELOCITY (u) = 0.5 m/s.
FINAL VELOCITY (v) = 0 m/s.
TIME (t) = 0.5 s

THEREFORE, ACCELERATION (a) = (v-u)/t
= ((0-0.5)/0.5) m/s²
= - 1 m/s² (retardation)

SO, ACTUAL ACCELERATION = 1 m/s²

NOW, FROM NEWTON'S SECOND LAW OF MOTION,

FORCE (F) = MASS (m) × ACCELERATION (a)
=> F = 0.07 × (1) N
=> F = 0.07 N [ANSWER]


✨✨✨✨ ALWAYS BE BRAINLY ✨✨✨✨

Answer 2

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❤ HERE IS YOUR ANSWER ______________________________


MASS OF CRICKET BALL (m) = 70 g = 0.07 kg. 
INITIAL VELOCITY (u) = 0.5 m/s. 
FINAL VELOCITY (v) = 0 m/s. 
TIME (t) = 0.5 s

THEREFORE, ACCELERATION (a) = (v-u)/t
= ((0-0.5)/0.5) m/s²
= - 1 m/s² (retardation) 

SO, ACTUAL ACCELERATION = 1 m/s²

NOW, FROM NEWTON'S SECOND LAW OF MOTION, 

FORCE (F) = MASS (m) × ACCELERATION (a) 
=> F = 0.07 × (1) N
=> F = 0.07 N [ANSWER] 


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⛔ I HOPE IT HELPS YOU ⛔
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