A cricket ball of massb145 gm is moving with a velocity of 14 m/s and is being hit by a bat so that the ball is turned back with a velocity of 22 m/s the force of blow acts on the ball for 0.015 sec.find the average force exerted by the ball on the ball.
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A cricket ball of mass 145 g moves with a velocity of 14 m/s and is hit by a bat so that the ball turns back with a velocity of 22 m/s. The force acts on the ball for 0.015 s. What is the average force exerted by the bat on the ball?
Initial momentum of the ball is p1=0.145×14 kg m/s.
Final momentum of the ball is p2=−0.145×22 kg m/s.
⇒ Change of momentum Δp=p2−p1=−0.145×22−0.145×14=−0.145×36 kg m/s.
Time taken for this change of momentum is t=0.015 s.
⇒ Rate of change of momentum Δpt=−0.145×360.015=−348 N.
Average force is the rate of change of momentum.
⇒ The magnitude of the average force is 348 N.
The direction of the force is along the direction of the final velocity of the ball.
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