Question

.A cricket ball reaches from M to N after successive displacement, calculate the total displacement, given
sin 37o

= 0.60 and cos 37o

= 0.80

plz answer this question With a explanation and solution ..
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Answer 1

Answer:

Explanation:

Sidyandex

From above, we can take all the vectors at a point m and resolve the values along X and Y axis to get total displacement:

X=Acos30-15+5cos37=A root 3/2-11:

Y=asin30+7-5sin 37=a/2 +4

So, resultant vector=displacement =  √(X2 +Y2))  =   (a√3/2 -11)2  +(a/2+4)2.By solving the above we can get the displacement.

Mass of the ball ,a , is not indicated.

So, value could not be calculated.

Answer 2

Answer:

Total displacement is 8.6 m

Explanation:

MB = 10 cos30° i + 10 sin 30° j =  5√3 i + 5 j

BC = 7 j

CD = - 15 i

DN = 5 cos 37° i - 5 sin37° j = 5 x 0.6 i - 5 x 0.8 j = 3i - 4j

From vector polygon

Vector MN = MB + BC + CD + DN

                  = (5√3 -15+3) i + (5 +7 -4) j

                  = ( 5 x 1.73 - 12) i + 8 j

                  = - 3.35 i + 8j

| MN | =$\sqrt{( 11.2 + 64)}$ = 8.6 m

α = tan⁻¹(3.35/8) = 22.72 ° (with vertical direction)

∴ The displacement is 8.6 m making an angle of 22.7° with the vertical