Question

a cricket ball thrown vertically upwards with an acceleration of 10m/s reaches a maximum height of 5m. Find the initial speed of the ball and the time taken to reach the highest point ​

Answer 1

Answer:

u is 10 and t is 1

Step-by-step explanation:

1)v^2 +=u^2+ 2as

2)s=ut +1/2(at^2)

(1)0^2=u^2 +2×-10×5=u^2+100

...u=10

(2) 5=10 *t+1/2(-10×t^2)

..10=20t-10t^2

t must be 1