Question

A cricket ball thrown vertically upwards with
an acceleration of 10m/s² reaches a maximum
height of 5m. Find the initial speed of the ball
and the time taken to reach the highest point?​

Answer 1

Answer:

10 m/s, 1s

Explanation:

h = 5m

a = - 10m/s² (As it is against gravity)

v = 0 (Since at max height, the v becomes 0)

So, by applying Kinematics equation:

v²= u² + 2ah

0= u² - 2×10×5

u²=100

u=10m/s

Now apply another Kinematics Formulae

v = u +at

0 = 10 - 10t

t = 1s

Answer 2

Answer:

as rhe ball is thrown upward hence it's final velocity will be 0m/s.

So, using 3rd eq. of motion,

v^2-u^2=2as

(0) ^2-u^2=2×10×5.

-u^2= 100

-u= √100

u=-10m/s..

and for time taken,

v=u+at

0=(-10) +10×t.

10=10t.

t= 10÷10=1sec....