Question

A cricket boll is throw verticaly upwirds with a spped of 19.6m/s.h ow hight will it rise ? how long the body will rise. neglect air resistancel​

Answer 1

Explanation:

Given that,

Initial velocity u=19.6m/s

Final velocity v=0

Time t=6sec

The acceleration is

We know that,

  v=u+at

 0=19.6+a×6

 a=−3.26m/s2

Now, the height is

From equation of motion

  s=ut+21at2

 s=19.6×6−21×3.26×36

 s=58.9

 s=59m

Hence, the height of the tower is 59 m