Question

A cricket bowler tosses a ball vertically upwards with an initial speed of 12m/s

a) How long does the ball take to reach its maximum height?
b) How long does the ball take to reach 5 metre above its release point? (g=10m/s²)
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Answer 1

${\tt{\red{\boxed{T \: = \: \frac{u}{g}}}}}$

$a) \: t \: = \: \frac{12}{10} </p><p> \\ t = 1.2 \: s$

$height \: = 5m \\ \\ u \: = \: 12 \: m/s \\ \\ t \: = \: ?$

.

using the realtion ,

${\tt{\pink{\boxed{s \: = ut \: + \: \frac{a {t}^{2} }{2}}}}}$

$→a \: = 10 \: m/ {s}^{2}$