A cricket match, if a batsman hits a boudnary 8 times out of 40 balls he plays.then, the probability that he did not hit aboundary. *
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Answered by
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Answer:here is your answer
Step-by-step explanation:
let E be the event of player not hitting boundary
Total balls = 40
Boundaries =8
So no. Of balls with no boundaries = 40-8 =32 balls
So P(E)= total number of balls with no boundary/
Total number of balls played
P(E)=32/40
= 4/5
So the probability of batsman not hitting boundary is 4/5
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Answered by
0
Answer:
4/5
Step-by-step explanation:
Hope this helps
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