Question

A cricket player catches a ball of mass 100 gm, moving
with velocity of 10 m/s. If the ball is caught and
stopped in 0.02 second, the average force exerted by
ball on the hand of player is nearly

Answer 1

Answer:

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Answer 2

force = m × dt + dv

since the ball is caught , hence final velicity is zero .

so here dv = 10 -0 = 10 and dt = 0.02

F = 100/100 × 10 /0.02

answer is 50N