Question

A cricket player has an average score of 30 runs for
42 innings played by him. In an innings, his highest
score exceeds his lowest score by 100 runs. If these
2 innings are excluded, his average of the remaining
40 innings is 28 runs. His highest score in an innings
is? ​

Answer 1

Answer:

Let the lowest score of the cricketer be x.

∴ Cricketer's highest score would be (x + 100)

According to the Question, (ATQ)

So,

      x + (x + 100) =  42 x 30 - 40 x 28

⟹  2x + 100 = 1260 - 1120 = 140

⟹  2x = 40

⟹   x =  20

∴ His highest score in an innings is : -

(x + 100) = (20 + 100)

= 120

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By the way my favorite cricketer is AB De Villiers