A cricket player has an average score of 30 runs for
42 innings played by him. In an innings, his highest
score exceeds his lowest score by 100 runs. If these
2 innings are excluded, his average of the remaining
40 innings is 28 runs. His highest score in an innings
is?
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Answer:
Let the lowest score of the cricketer be x.
∴ Cricketer's highest score would be (x + 100)
According to the Question, (ATQ)
So,
x + (x + 100) = 42 x 30 - 40 x 28
⟹ 2x + 100 = 1260 - 1120 = 140
⟹ 2x = 40
⟹ x = 20
∴ His highest score in an innings is : -
(x + 100) = (20 + 100)
= 120
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