Question

A cricket player has an average score of 40 runs for 52 innings played by him. In an innings his highest score exceeds his lowest score by 100 runs. If these two innings are excluded, his average of the remaining 50 innings is 38 runs. Find his highest score in an innings.
A) 80
B) 40
C) 140
D) 60

Answer 1

Answer:

Highest score in an innings = (C) 140

Step-by-step explanation:

Let the highest score of the player = H

Difference between lowest and highest score is 100

∴ His lowest score

L = H - 100  .... (1)

Average score for 52 innings is given as 40 runs

∴ Total runs scored in 52 innings

T52 = 52 × 40 = 2080 ..... (2)

When the two innings (higsest and lowest score) are excluded, average for the rest 50 innings is 38

∴ Total score for 50 innings

T50 = 50 × 38 = 1900 .... (3)

From enq 2 and 3, we can conclude that,

Totla score for 52 innings = Total Score  for 50 innings + Highest score + Lowest score

∴ T52 = T50 + H + L

Substituing from eqn 1,2 and 3, we get

2080 = 1900 + H + (H-100)

∴ 180 + 100 = 2H

∴ 2H = 280

∴ H = 140

∴ Highest Score in an inning = (C) 140