a cricket player holds a cricket ball of mass 0.1kg by moving his hands backwards by 0.75m. if the initial velocity of the ball is108kmh¯¹, calculate the retarding force applied by the player.
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m=0.1 kg , s=0.75m , u=108 km/h=30 m/s , v=0 m/s
2as=v^2 - u^2
2*a*0.75 = -900
a = -900/1.5
a = -600m/s^2
F = ma
F = 0.1*-600
F=-60N
2as=v^2 - u^2
2*a*0.75 = -900
a = -900/1.5
a = -600m/s^2
F = ma
F = 0.1*-600
F=-60N
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12
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Explanation:Secondary SchoolPhysics 5+3 pts
a cricket player holds a cricket ball of mass 0.1kg by moving his hands backwards by 0.75m. if the initial velocity of the ball is108kmh¯¹, calculate the retarding force applied by the player.
Report by Golu6590 14.08.2018
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m=0.1 kg , s=0.75m , u=108 km/h=30 m/s , v=0 m/s
2as=v^2 - u^2
2*a*0.75 = -900
a = -900/1.5
a = -600m/s^2
F = ma
F = 0.1*-600
F=-60N
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