Question

A cricketer can throw a ball to a maximum horizontal distance of hundred metre how high above the ground can the cricketer throw the ball with the speed

Answer 1

Answer:

Maximum height reached by ball

= 25 m

Step by step explanations :

given that,

A cricketer can throw a ball to a maximum horizontal distance of 100 m

here,

we have the maximum horizontal distance = 100 m

we know that,

maximum horizontal distance can thrown at the angle of 45° at a certain speed

so,

let the speed by which ball was thrown be u

here,

θ = 45°

distance travelled by ball = 100 m

gravitational acceleration = -10 m/s²

so,

According to the question,

u² sin2θ/g = 100

putting the values,

u² sin2(45°)/-10 = 100

u² sin90°/-10 = 100

u² × 1 = -1000

u² = -1000

now,

maximum height at 45°

➪ u² sin² 45/2g

putting the value of u²

➪ -1000 × 1/√2 × 1/√2 /2 × (-10)

➪ -1000 × ½ /-20

➪ -1000/-40

➪ 25 m

so,

Maximum height reached by ball

➪ 25 meter

Answer 2

Answer:

Maximum height = 25 meter

Step by step explanations :

given the maximum distance travelled by the ball = 100 m

so,

θ = 45°

distance travelled by ball = 100 m

gravitational acceleration = -10 m/s²

so,

u² sin2θ/g = 100

here,

u = initial velocity

u² sin2(45)/-10 = 100

u² sin90°/-10 = 100

u² × 1 = -1000

u² = -1000

u² sin² 45/2g

= -1000 × 1/√2 × 1/√2 /2 × (-10)

= -1000 × ½ /-20

= -1000/-40

= 25 m

so,

Maximum height = 25 meter